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x^2-30x=-224
We move all terms to the left:
x^2-30x-(-224)=0
We add all the numbers together, and all the variables
x^2-30x+224=0
a = 1; b = -30; c = +224;
Δ = b2-4ac
Δ = -302-4·1·224
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2}{2*1}=\frac{28}{2} =14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2}{2*1}=\frac{32}{2} =16 $
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